Which function has a removable discontinuity?

Reasoning:

The denominator in choice A factors to (x-2)(x+1). We have a pair of "x-2" terms that cancel leaving us with 1/(x+1). We cannot plug x = -1 into the simplified result because it leads the denominator x+1 to turn into 0.

Also, we cannot plug x = 2 into p(x) for choice A either. It doesn't lead to issues for 1/(x+1) but the original function before we simplify will have x = 2 lead to a division by zero error.

A vertical asymptote is located at x = -1

The removable discontinuity happens when x = 2, so there will be a hole here.

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

we need the options

step-by-step explanation: