X+2y greater than or equal to 10

3x-4y greater than 12

what ordered pairs are solutions to the set of equations
16,9
10,2
8,1
2,6
4,-4
14,-1
-4,2

16, 9

10, 2

Step-by-step explanation:

Given the two equations:

x + 2y ≥ 10

3x - 4y > 12

You need to multiply the first fraction by a factor of '2' in order to get the opposite coefficients of 'y' to eliminate that variable:

2(x + 2y ≥ 10)

 2x + 4y ≥ 20

+ 3x - 4y > 12

   5x > 32

    x > 6.4

Solve for 'y':

6.4 + 2y ≥ 10

2y ≥ 3.6

y ≥ 1.8

The only set of ordered pairs that have x > 6.4 and y > 1.8 are:

16, 9 and 10, 2

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!