The data set below has an outlier 2,10,10,11,11.12,12,12,13,14,14
which value is changed the most by removing the outlier

Mean

Step-by-step explanation:

The mean with the outlier is

(2+10+10+11+11+12+12+12+13+14+14)/11  = 11

The mean without the outlier is

(10+10+11+11+12+12+12+13+14+14)/10  = 11.9

The median is the middle number

With the 2 it is 12

Without the 2 it is 12

Mode is most often

With the 2 it is 12

Without the 2 it is 12

were is the equation

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.