Ana was given the following problem for homework to analyze:

suppose a volleyball player serves from 1 behind the back line. if no other player touches the ball, it will land in bounds. the equation

ℎ()= −4.92 + 3.28 +1.7 gives the ball’s height, ℎ, in meters in terms of time, , in seconds.

part a: finally, ana states that the ball will hit the ground after 1.012 seconds. is she correct? justify your answer.

Step-by-step explanation:

The variable t is missing in the given equation as it should read:

ℎ(t)= −4.92t^2 + 3.28t + 1.7

When the ball will hit the ground, h=0

−4.92t^2 + 3.28t + 1.7 = 0

Using the quadratic formula to find the solution,

t = -0.34 or 1.01

As time cannot be negative, h=0 when t=1.01s. So Ana is correct.

The answer is very close, within the  margin of error.

Step-by-step explanation:

When the ball hits the ground, h(t) will equal 0

0 =  −4.92t^2 + 3.28t +1.7

Using the quadratic equation

-b ± sqrt(b^2 -4ac)

2a

where a = -4.92  b = 3.28 and c = 1.7

-3.28 ± sqrt(3.28^2 -4(-4.92)1.7)

2(-4.92)

t≈-0.342418

t≈1.00908

The answer is very close, within the  margin of error.

55

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3