Find the vertex of the function f(x)=2x^2-8x+6

find the vertex of the function f(x)=2x^2-8x+6

$450

step-by-step explanation:

first, you have to multiply 150x2=300

next, you have to add 150+300= 450

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

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