Asurvey showed that 82% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. if 12 adults are randomly selected, find the probability that at least 11 of them need correction for their eyesight. is 11 a significantly high number of adults requiring eyesight correction?

Pr(X >= 11) = 0.33586800937

Step-by-step explanation:

This scenario can be modeled by a binomial distribution model.

The probability of success, p = 0.82 is constant.

The are 12 independent trials.

We let the random variable X denote the number of adults who need correction for their eyesight. We are then to determine the probability that X is at least 11;

Pr(X=11 or 12) = Pr(X=11) + Pr(X=12)

                       =  0.33586800937

11 is significantly a high number of adults requiring eyesight correction.

i pretty sure it is