The length of a rectangle is 5 more than 2 times its width. the perimeter is 40 inches. what is the width of the rectangle?

The width of rectangle = 5 inches

Step-by-step explanation:

Formula:-

Permeter of rectangle = 2(l + b)

l - Length of rectangle

b - Breadth of rectangle

It is given that,the length of a rectangle is 5 more than 2 times its width. The perimeter is 40 inches

Let  'x' be the width of rectangle.

length of rectangle = 2x + 5

To find the value of x

It is given that perimeter = 40 inches

Perimeter = 2(l + b) = 40

2(2x + 5 + x) = 40

3x + 5 = 20

3x = 20 - 5 = 15

x = 15/3 = 5

To find the length and width

Width = x = 5 inches

Length = 2x +5 = 2*5 + 5 = 15 inches

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

current in the circuit at time t is /, then the power delivered to the resistor is

step-by-step explanation: