(i will give 30 points)
for the function f(x) = (8-­2x)2 ,find f-­1 . determine whether f­-1 is a function.

answer choices:
f­-1(x) = ±8+x2−−−√; f­-1 is a function

f­-1(x) = ±8+x2−−−√; f­-1 is not a function

f­-1(x) = 8±x√2; f­-1 is not a function

f­-1(x) = 8±x√2; f­-1 is a function

Answer: 900°

good luck on your studies! : )

david edward.

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.