Which of the following are the coordinates of the vertex of y= x^2 - 10x +2?

The vertex would be (5, -23)

Step-by-step explanation:

To find this, we need to start by finding the x value of the vertex. We do so by using -b/2a, in which b is the coefficient of the x term and a is the coefficient of the x^2 term.

-b/2a

-(-10)/2(1)

10/2

5

Now that we have the x value, we can plug into the equation to find the y value

y = x^2 - 10x + 2

y = 5^2 - 10(5) + 2

y = 25 - 50 + 2

y = -23

The vertex of given equation is (5,-23).

Step-by-step explanation:

We have given an equation:

y= x² - 10x+2

We have to find the vertex of given equation.

y= (x-a)²+b is vertex form of  quadratic equation   where ( a,b) is vertex of equation.

Adding and subtracting (-5)² to given equation, we have

y = x²-2(5)(x)+2+(-5)²-(-5)²

y = (x-5)²+2-25

y = (x-5)²-23

Comparing to the vertex form , we have,

a = 5 and b = -23

Hence, the vertex of given equation is (5,-23).

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )