Determine the eccentricity, the type of conic, and the directrix for r = 9/1+6 cos theta. (picture provided below)

Eccentricity = 6

Type of conic section; Hyperbola

Directrix; x = 3/2

Step-by-step explanation:

The given polar equation of the conic section is in standard form;

The eccentricity is given by the coefficient of cos theta in which case this would be the value 6. Therefore, the eccentricity of the this conic section is 6.

The eccentricity is clearly greater than 1, implying that the conic section is a Hyperbola.

Since the conic section is in standard form, the numerator is the product of eccentricity and the value of the directrix, that is;

e*d = 9

6*d = 9

d = 3/2.

Since the denominator has a plus sign then the hyperbola opens towards the left and thus the equation of its directrix is;

x = 3/2

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!