Mns(s) + 2 h+ < ===> mn2+ + h2s(g) at 25 °c the solubility product constant, ksp, for mns in 5 x 10¯15 and the acid dissociation constants k1 and k2 for h2s are 1 x 10¯7 and 1 x 10¯13, respectively. what is the equilibrium constant for the reaction represented by the equation above at 25 °c? (a) 1 x 10¯13 / 5 x 10¯15 (b) 5 x 10¯15 / 1 x 10¯7 (c) 1 x 10¯7 / 5 x 10¯20 (d) 5 x 10¯15 / 1 x 10¯20 (e) 1 x 10¯20 / 5 x 10¯15

the answer is c.

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;