What are the coordinates of the focus of the parabola?

y= −1/12x^2−x+6

(−6, 6)

(6, 6)

(6, 9)

(−6, 9)

The coordinates of the focus of the parabola are (-6,6)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

where

(h,k) is the vertex

(h,k+(1/4a)) is the focus

in this problem we have

Convert to vertex form

------> equation in vertex form

The vertex is the point (-6,9)

The focus is (h,k+(1/4a)) ------> (-6,9+(1/4(-1/12))-----> (-6,9-3)----> (-6,6)