Martin puts two bowls of fruit out for his friends. the bowl of grapes has 9 green grapes and 16 red grapes. the bowl of tangerines has 7 seeded and 3 seedless tangerines.

martin's friend chooses a random grape and a random tangerine. what is the probability that she chooses a green grape and a seedless tangerine?

The probability that she chooses a green grape and a seedless tangerine is 27/250

Probability is the likelihood or chance that an event will occur.

Probability = Expected/Total outcome

If the bowl of grapes has 9 green grapes and 16 red grapes and the bowl of tangerines has 7 seeded and 3 seedless tangerines.

Pr(grape) = 9/25

Pr(seedless tangerine) = 3/10

Pr(a green grape and a seedless tangerine) = 9/25 * 3/10

Pr(a green grape and a seedless tangerine) = 27/250

Hence the probability that she chooses a green grape and a seedless tangerine is 27/250

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Step-by-step explanation:

There are two requirements: a green grape and a seedless tangerine

For grapes, total number of grapes is 9+16 = 25 and 9 are green

Prob (green grape)=9/25

For tangerines, total number of tangerines is 7+3 = 10 and 3 are seedless

Prob (seedless tangerine)=3/10

Prob (a green grape and a seedless tangerine)=9/25*3/10

=27/250

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )