Solve a triangle with a=32, b=38, and c=46.

Step-by-step explanation:

we have a triangle with

 a=32, b=38, and c=46

We can use the cosine rule to find the angles

It is

so plugging all the values we get

A= 43.5

Now for angle B , the formula is

plugging all the vaues again we get

B= 54.8

Now since for a triangle A+B+C =180

so C = 180 - 43.5- 54.8

C=81.7

option a

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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