Mrs. cho wrote the following problem on the board. what should mrs. cho do next? find a common denominator for the two fractions. divide the numerator and denominator of the first fraction by x2 and y. multiply the numerators, multiply the denominators, and then simplify. multiply the first fraction by the reciprocal of the second fraction.

The answer is:  Multiply the numerators, multiply the denominators, and then simplify.

Let's discard each given option in order to find the correct one.

Find a common denominator for the two fractions:

Incorrect, there Mrs. Cho does not need to find a common denominator since it's a fraction multiplication. We find common denominators when we are doing additions or subtractions of fractions.

Divide the numerator and denominator of the first fraction by x2 and y:

Incorrect, Mrs. Cho does not need to divide the numerator and denominator of the first fraction by x2 and y, doing that would not help at all, it's a useless step.

Multiply the numerators, multiply the denominators, and then simplify:

Correct, Mrs. Cho should multiply and then, simplify the result:

As we can see,the fraction is simplified because the first fraction numerator and the second fraction denominator are equal.

Multiply the first fraction by the reciprocal of the second fraction:

Incorrect, Mrs. Cho does not need to multiply the first fraction by the reciprocal of the second fraction since it's not a fraction division.

Have a nice day!

answer: are you

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages