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classify -6x^5 +4x^2 +11 by degree.
quintic
cubic
quartic
quadratic

The degree is of degree 5, hence the function is classified as Quintic: Option A is correct.

An equation is categorized as a quadratic, linear, or polynomial equation depending on the degree of the polynomial.

The highest exponential value of the leading term in an expression is the degree of the function.

Given the function -6x^5 +4x^2 +11, we can see that the leading terms have a degree of 5 showing that the function is a polynomial function.

Since the degree is of degree 5, hence the function is classified as Quintic

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guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: