Find the surface area of the square pyramid using a net

532 yd^2

Step-by-step explanation:

The base of this pyramid is square, and the length of each side is 14 yd.

The equation for the area of a triangle is

A = (1/2) (base) (height), which here is equal to:

A = (1/2) (14 yd (12 yd) = 84 yd^2.

Here there are four such sides, so the total area of the four sides is:

4(84 yd^2) = 336 yd^2.

If we are to calculate and include the surface area of the base, we use the area of a square formula:  A = s^2, where s is the length of one side of the square.

Here the area of the base is A = (14 yd)^2 = 196 yd^2.

Adding up the areas of the sides and the area of the base, we get the total surface area

At = 336 yd^2 + 196 yd^2 = 532 yd^2

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1