i have 36 coins with a total value of $2.35. the coins are 5-cent and 10-cent coins. how many 5-cent coins do i have?

25 nickels, 11 dimes

Step-by-step explanation:

let n (nickel) = amount of 5 cent

let d (dime) = amount of 10 cent

5n+10d=235

n+d=36

I

V

d=36-n

substitute this in the first equation

5n+10(36-n)=235

5n+360-10n=235

-5n+360=235

-360        -360

-5n=-125

/-5     /-5

n=25

you have 25 nickels

if you have 36 total coins, subtract 25 from this and get 11

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

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