In triangle abc segment de is parallel to the side ac. (the endpoints of segment de lie on the sides ab and bc respectively).

find de, if ac=18dm, ab=15dm, and ad=10dm.

6 dm

Step-by-step explanation:

Triangle DBE is similar to triangle ABC, so their side lengths are proportional.

DE/AC = DB/AB

The length of DB can be found from ...

DB +AD = AB

DB = AB -AD = (15 -10) dm = 5 dm

So, we can fill in the proportion:

DE/(18 dm) = (5 dm)/(15 dm)

DE = (18 dm)·(1/3) . . . . . . . . . . simplify, multiply by 18 dm

DE = 6 dm

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step-by-step explanation:

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