Find two consecutive even integers such that the smaller added to two times the larger gives a sum of 16

Integer 1 = 4

Integer 2 = 6

Step-by-step explanation:

If you have two unknown consecutive even integers, you could call them as follows:

Integer 1 = x

Integer 2 = x+2

Your question claims that the smaller added to two times the larger gives a sum of 16.

So

Integer 1 + 2*(Integer 2) = 16

x + 2*(x+2) = 16

x + 2x + 4 = 16

3x = 12

x = 4

Since x is 4, this is your smaller integer. Your larger integer, therefore, would be x + 2, or 4 + 2 = 6.

Integer 1 = 4

Integer 2 = 6

Hope this helps.

a. -0.3 > -0.33

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076