Maria is ten years older than josé, and next year she will be twice as old as josé. how old are they now?

Maria's age now is 19 years old

Jose's age now is 9 years old

Explanation:

Assume that Maria's current age is x and that Jose's current age is y

We are given that:

1- Maria is 10 years older than Jose.

This means that:

x = y + 10 > equation I\

2- Next year, Maria will be twice as old as Jose.

This means that:

Maria's age next year = 2 * Jose's age next year

x + 1 = 2(y+1)

x + 1 = 2y + 2 > equation II

Substitute with equation I in equation II and solve for y as follows:

x + 1 = 2y + 2

y + 10 + 1 = 2y + 2

y + 11 = 2y + 2

2y - y = 11 - 2

y = 9

Substitute with y in equation I to get x as follows:

x = y + 10

x = 9 + 10

x = 19

Based on the above calculations:

Maria's current age = x = 19 years old

Jose's current age = y = 9 years old

Hope this helps :)

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

faster, im not sure why but i know it is faster