Fernando has some nickels, dimes, and quarters that are worth a total of $3.25. he has twice as many dimes as nickels. he has 3 more quarters than nickels.

how many nickels, dimes, and quarters does fernando have?

let x represent the number of nickels.

write and solve a linear equation in one variable.

Number of nickels = 5

Number of dimes = 10

Number of quarters = 8

Step-by-step explanation:

Fernando has a total of nickels + dimes + quarters = 3.25$

Let the number of nickels = x

Then x(.05) + dimes(.10) + quarters(0.25) = 3.25(1)

He has twice as many dimes as nickels

dimes = 2×nickels

dimes = 2x(2)

He has 3 more quarters than nickels

quarters = nickels +3

quarters = x +3(3)

From equations 1, 2, and 3.

x(.05) + 2x(.10) + (x + 3)(.25) = 3.25

.05x + 0.2x + 0.25x + .75 = 3.25

5x + 20x + 25x + 75 = 325

50x = 325 - 75

50x = 250

x = 5

Therefore the number of nickels are 5

from equation 2 number of dimes are 10

and from equation 3 number of quarters are 8.

after simplifying it i got: -36.25 as my answer. hope that !