What are the solutions of the equation x^4-5x^2-36=0? use factoring to solve.

+3 and -3, and + 2i or - 2i, which is the second answer.

Step-by-step explanation:

(x^2 -9)(x^2 + 4) is the factorization. Now set each side equal to zero:

(x^2-9) = 0; so x^2= 9, and x = square root of 9 which is +3 or -3.

(x^2) + 4 = 0; so x^2 = -4, and x will equal the square root of NEGATIVE 4, which is plus or minus 2i

26

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.