Arectangular room is 4 meters longer than it is wide, and its perimeter is 32 meters. find the dimension of the room.

The dimensions of the room are 6 m and 10 m

Step-by-step explanation:

Let the width of the room is x

∴ Its length = x + 4

∵ The perimeter of the rectangle = 2(length + width)

∴ 2(x + 4 + x) = 32

∴ 2(2x + 4) = 32

∴ 4x + 8 = 32

∴ 4x = 24

∴ x = 24/4 = 6

∴ The length = 6 + 4 = 10 m

∴ The width = 6 m

i think it would be 42cm

lol.

it's ok we all do this sometimes.

-aparri