What is the solution to this system of linear equations?
2x+y=1
3x-y=-6

a. (-1,3)
b. (1,-1)
c. (2,3)
d. (5,0)

A. (-1,3)

Step-by-step explanation:

To solve this problem, enter equation (i) in equation (ii)

2x+y=1  (i)

y= 1 -2x

3x-y=-6   (ii)

3x - (1-2x) = -6

3x - 1 +2x = -6

5x = -5

x = -1.  (iii)

Replace (iii) in (i) and clear y

2(-1) + y = 1

y = 1+2

y = 3

The solution is Option A. (-1, 3)

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.

and?

step-by-step explanation: