Given right triangle mnl, what is the value of cos(m)?
a. 3/5
b. 3/4
c. 4/5
d. 5/3

C. 4/5

Step-by-step explanation:

We have that cos(M) = Adjacent side/Hypotenuse

Where:

Hypotenuse (h) = 25

We do not know the adjacent side (a), but the opposite side (b).

Then we use the Pythagorean theorem:

Then:

Option C

The correct answer is option C. 4/5

Step-by-step explanation:

Pythagorean theorem:-

Hypotenuse² = Base² +  Height²

It is given a right triangle ABC.

To find the value of MN

Hypotenuse² = Base² +  Height²

ML = 25

NL  =15

MN = ?

ML²  = NL² + MN²

MN² = ML² - NL² =  25² - 15² = 625 - 225 = 400

MN = √400 = 20

To find Cos(M)

Cos(M) = Adjacent side/Hypotenuse

Cos(M) = MN/ML= 20/25 = 4/5

The correct answer is Option C. 4/5

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl