Drag each system of equations to the correct location on the table. classify each system of equations as having a single solution, no solution, or infinite solutions.

Step-by-step explanation:

No solution and all solution.  An example of no solution is this: 2 + x = 3 + x if you subtract the ‘x’s, then you get 2=3 which is incorrect.  An example of all solutions would be something like 3 + x =  x + 3. No matter what ‘x’ is, 3 = 3.

oof

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: