Complete the equation so it has infinitely many solutions. 4x + 7 = 4(x + 3) –

The completed equation must be 4x + 7 = 4(x + 3) – 5

Step-by-step explanation:

For this equation to have infinitely many solutions, we must solve for x and reach a point where we have "0x = 0".

Notice that, x = ... -2, -1, 0, 1, 2 ... are all solutions of "0x = 0".

We will call the missing term "t", then the given equations is...

4x + 7 = 4(x + 3) – t

We distribute 4 over the parentheses on right side...

4x + 7 = 4x + 12 – t

We substract 7 on both sides...

4x + 7 - 7 = 4x + 12 – t - 7

4x = 4x + 5 – t

We substract 4x on both sides...

4x - 4x = 4x + 5 – t  - 4x

0x = 5 - t

As state above, this equation will have infinitely many solutions if the right side is 0...

5 - t = 0

5 = t

The answer is 5.

Step-by-step explanation: Did it on Edge, hope this helps :D

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step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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