What are the coordinates of the point that is 1/4 of the way from a to b ?

((X_2 - X_1)/4, (Y_2 - Y_1)/4)

Step-by-step explanation:

C = The new point

X_1 = The x coordinate of A

X_2 = The x coordinate of B

X_3 = The x coordinate of C

Y_1 = The y coordinate of A

Y_2 = The y coordinate of B

Y_3 = The y coordinate of C

The distance between A and the new point, C, is equal to 1/4 the distance from the X coordinate of A to the X coordinate of b.

So,  X_3 = (X_2 - X_1)/4

The Y is the same thing but for the Y coordinate.

Y_3 = (Y_2 - Y_1)/4

This means that the coordinates of C are equal to ((X_2 - X_1)/4, (Y_2 - Y_1)/4)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

y - 25 = 2 ( x - 10 ) should be the answer