After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are a'(6, 3), b'(–2, 1), and c'(1, 7). what are the coordinates of the vertices of the pre-image?

a

b

c

A- (3,-6)

B- (1,2)

C- (7,-1)

Step-by-step explanation:

You start off with A- (6,3) B- (-2,1) C- (1,7), You then apply the rule.

A- (6,3) turns into (3,-6)

B-(-2,1) turns into (1,2)

C-(1,7) turns into (7,-1)

Those are the answers

i think the answer is fried chicken ; >

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204