Does the triangle with the side lengths of 6ft, 7ft, and 8 ft form a right triangle

  No.

Step-by-step explanation:

When the side lengths are consecutive integers, only the lengths 3, 4, and 5 will form a right triangle.

  8^2 ≠ 6^2 + 7^2 . . . . for a right triangle, the square of the hypotenuse must be the sum of the squares of the legs

  64 ≠ 36 + 49 = 85

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation