If the divisor is a two digit number, can you write a rule for how many digits in the dividend you will need to look at ti complete the first step in dividing? pls explain your answer. pls i need rhe answer asap! tomorrow is school for me and i didn’t finish my homework yet soo pls!

Mmh same for me! QwQ I see your a Gacha person too! Anyways, let's get on with the question. Well I'm not so sure about this! :< So The Divisor is a two-digit number (For example, 10 since it has 2 numbers/2 digits). Next we have to write a rule for how many digits in the dividend you will need to look at to complete the first step in dividing. Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction. The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. This is a fraction way (Read this carefully) I PUT ThiS PART IN CAPS SO YOU CAN SEE THE WARNING XD. Alright so, the warning is this is for fractions.

We have to find it for a two-digit number So, Divide the first number of the dividend (or the two first numbers if the previous step took another digit) by the first digit of the divisor. Write the result of this division in the space of the quotient. Multiply the digit of the quotient by the divisor, write the result beneath the dividend and subtract it. There! I hope this helps you this took a long time.

~ Kana ~

| Have a wonderful day and hope I helped you! :3 |

i leave the calculator work to you.

7. diameter 4 miles, circumference 4π miles

8. radius 0.2 miles, circumference 0.4π miles

[this is a bad problem because the actual radius of a car on the track is less than 0.2 miles so the answer is less than 0.4π miles]

9. radius 6 feet, circumference 12π feet

10. diameter 14 cm, circumference 14π cm

11. diameter 4.8 feet, circumference 4.8π feet

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: