Is g(x) = x(x - 4)[x-i(square root of 7)][x+i(square root of 7)] the factored form of f(x) = x^4+4x^3+7x^2+28x

No.

It's  x^4 - 4x^3 + 7x^2 - 28x.

Step-by-step explanation:

(x - √7 i)(x +√7i)

= x^2 + √7x i - √7x i - 7 i^2

= x^2 - 7 * -1

= x^2 + 7

g(x) = x(x - 4)(x^2 + 7)

= x(x^3 + 7x - 4x^2 - 28)

= x^4 - 4x^3 + 7x^2 - 28x.

susie has 7 apples