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quadrilateral abcd is an isosceles trapezoid. m∠abc = 120°

what is m∠bcd?

m<BCD = 60

Step-by-step explanation:

We assume that sides AB and DC are parallel. Angles ABC and BCD are same side interior angles of parallel lines cut by a transversal, so they are supplementary.

m<ABC + m<BCD = 180

120 + m<BCD = 180

m<BCD = 60

m<BCD = 60°

Step-by-step explanation:

It is given that, Quadrilateral ABCD is an isosceles trapezoid. m∠ABC = 120°

To find m<BCD

ABCD is an isosceles trapezoid.

From the figure we get,AB║ DC. And BC is a traversal on these parallel line.

<ABC and <BCD are the interior angle on the same side.

We know that the interior angles on the same side are supplementary.

Therefore, m<ABC + m<BCD = 180°

m<ABC = 120°

m<BCD = 180 - m<ABC = 180 - 120 = 60°

Therefore m<BCD = 60°