Can you factor y^2+49 using the differences of two squares form? why or why not?

No you can't, because if you were to factor this furthur you wouldn't end up with y^2+49 when checking to see if your factorization works. This could work if the equation is y^2-49 because then when you factor it would look like this:

false

ajkdfbwladnfwisafrw

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )