The sum of two consecutive even integers is 158. find the least of the two integers.

78 and 80

Step-by-step explanation:

Two consecutive even integers means that they will go in groups of 2. For example 2 and 4 are consecutive even numbers.

To solve this problem you'll need to set an equation equal to 158. We can call the first even integer x and the second CONSECUTIVE even integer x + 2.

Make these two expressions add up to equal 158 and solve for x.

(x) + (x + 2) = 158

Combine like terms.

2x + 2 = 158

Subtract 2 from both sides of the equation.

2x = 156

Divide both sides of the equation by 2.

x = 78

The first integer is 78, now substitute this value into the expression representing the second integer.

(78) + 2 = 80

The second integer is 80.

The least of the two integers which are even consecutive integers are 78 and 80 and this can be determined by using the given data and arithmetic operations.

Given :

The sum of two consecutive even integers is 158.

Let the first even integer be 'x'. So, the second even integer which is consecutive to the first is (x + 2).

According to the given data, the sum of two consecutive even integers is 158. So, the mathematical expression is given by:

x + x +2 = 158

Simplify the above equation in order to determine the value of 'x'.

2x + 2 = 158

2x = 156

x = 78

So, the least of the two integers which are even consecutive integers is 78 and 80.

For more information, refer to the link given below:

link

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this