2x^2-5x-3=0 what values of x make this equation true?

The values of x are -1/2 and 3

Step-by-step explanation:

∵ 2x² - 5x -3 = 0

By using factorization

(2x + 1)(x - 3) = 0

2x + 1 = 0 ⇒ 2x = -1 ⇒ -1/2

x - 3 = 0 ⇒ x = 3

∴ The values of x are -1/2 and 3

x = -½ and x = 3  

Step-by-step explanation:

2x² - 5x - 3 = 0

Rewrite -5x as -6x + x

2x² - 6x + x - 3 = 0

Factor out 2x from the first pair and 1 from the second pair

2x(x - 3) + 1(x - 3) = o

Factor out (x - 3)

(2x + 1)(x - 3) = 0

Apply the Zero Product property

2x + 1 = 0     x - 3 = 0

Solve each equation

2x + 1 = 0     x - 3 = 0

    2x = -1         x = 3

      x = -½

The equation is true when x = -½ and when x = 3.

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)