Hi there!

can i get some with #2 and #6 calculus? show your work.

!

1.  36 -24x

2.  -6x/ (3x^2+5)^2

Step-by-step explanation:

2.

y = 1 - 3u^2

dy/dx = -6u du/dx

We can find du/dx

u = 3 -2x

du/dx = -2

Substituting back in for  u and du/dx

dy/dx = -6u du/dx

dy/dx = -6 (3-2x) (-2)

dy/dx = 12 (3-2x)

         = 36 -24x

6.  y = 1/u = u ^ -1

dy/dx = -1 u^-2 du/dx

u = 3x^2 +5

du/dx = 6x

Substituting back in for  u and du/dx

dy/dx = - (3x^2+5) ^-2 (6x)

         = -6x/ (3x^2+5)^2

c

step-by-step explanation:

c