Use the identity (x+y)(x2−xy+y2)=x3+y3 to find the sum of two numbers if the product of the numbers is 10, the sum of the squares of the numbers is 29, and the sum of the cubes of the numbers is 133.

enter your answer as a number, like this: 42

The sum of two numbers is 7.

Step-by-step explanation:

Given : the product of the numbers is 10, the sum of the squares of the numbers is 29, and the sum of the cubes of the numbers is 133.

Using identity and given details, we have to find the sum of two numbers.

Since, given that the product of the numbers is 10 that is

Also, given the sum of the squares of the numbers is 29 that is

and the sum of the cubes of the numbers is 133 that is

Using, the given identity ,

Substitute, the given values, we have,

Simplify , we get,

Divide both side by 19, we have,

Thus, the sum of two numbers is 7.

x+y = 7

Step-by-step explanation:

We have given that

The product of the numbers is 10

xy = 10

The sum of the squares of the numbers is 29

x²+y² = 29

The sum of the cubes of the numbers is 133

x³+y³ = 133

We have to find that the sum of two numbers.

x+y = ?

Using given formula, we have

(x+y)(x²-xy+y²) = x³+y³

(x+y)(x²+y²-xy) = x³+y³

Putting given value in above formula, we have

(x+y)(29-10) = 133

(x+y)(19) = 133

(x+y) = 133 / 19

x+y = 7 which is the answer.

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.