Peanut allergies among children. about 2% of children in the united states are allergic to peanuts. choose three children at random and let the random variable xx be the number in this sample who are allergic to peanuts. the possible values xx can take are 0, 1, 2, and 3.

what is the conditional probability that exactly two of the children will be allergic to peanuts, given that at least one of the three children suffers from this allergy?

(round your answer to six decimal places.)

p(x=2|x⩾1)p(x=2|x⩾1) =

P(X=2|X≥1) = 0.0199973.

Step-by-step explanation:

The chance that each of the three children is allergic to peanuts is independent. Each with a chance of 2% = 0.02.

X follows a binomial distribution with

.

The event includes

In other words, implies that .

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.

.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent