Let a= x^2 +4. rewrite the following equation in terms of a and set it equal to zero.
(x^2+4)^2+32=12x^2+48
which of the following are solutions for x?
a)-8
b)-2
c)4
d)0
e)2
f)-4
g)8

C and G

Step-by-step explanation:

(x^2+4)^2+32=12x^2+48 is written as .

We can simplify the expression using the term a by replacing x^2 + 4 with a.

This factors into (a-4)(a-8). Solve by setting each factor equal to 0 and solve for a.

a-4 = 0                 a=4

a-8=0                   a=8

6hryt%4578855