Will mark !
the graph of a polynomial function has zeros of 3 (multiplicity 2), and -7 (multiplicity 1).
write a function, in standard form, that could represent this function.

f(x) = x^3 + x^2 - 33x + 63

Step-by-step explanation:

The zeros are x = 3, x = 3, x = -7.

A polynomial function with zeros x1, x2, x3, ..., xn has the form:

f(x) = (x - x1)(x - x2)(x - x3) ... (x - xn)

The zeros of this function are 3, 3, -7.

The function is:

f(x) = (x - 3)(x - 3)(x - (-7))

f(x) = (x - 3)(x - 3)(x + 7)

Now we multiply out the right side.

f(x) = (x^2 - 6x + 9)(x + 7)

f(x) = x^3 + 7x^2 - 6x^2 - 42x + 9x + 63

f(x) = x^3 + x^2 - 33x + 63