Part 1: label points a, b, and c on the triangle.
given: in δabc, de is parallel to ac.

part 2: use the spaces provides below to complete a formal proof.
given: in δabc, de is parallel to ac
prove:

Step-by-step explanation:

Given parameters: In these two triangles side AC║DE and angle A is common in both the triangles.

We have to prove

As we know in two triangles if two angles are same then by AA theorem the triangles will be similar.

Since AC║DE and AB is a transverse.

Therefore ∠BDE=∠BAC

Similarly AC║DE and BC is a transverse

Therefore ∠BED=∠BCA

Here AA theorem fulfills the requirements of congruence in ΔABC≅ ΔBDE

Therefore all sides of these triangles will be in same ratio.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

chiken

step-by-step explanation: