Give the equation of the circle centered at the origin and passing through the point (0,3)

The equation would be x^2 + y^2 = 9

Step-by-step explanation:

In order to find this, start with the base form of the circle.

(x - h)^2 + (y - k)^2 = r^2

Now we input the center as (h, k).

(x - 0)^2 + (y - 0)^2 = r^2

x^2 + y^2 = r^2

Now we can input the radius of 3 in for r

x^2 + y^2 = 3^2

x^2 + y^2 = 9