What are the coordinates of the hole in the graph of the function f(x)
f (x) = x^2 + 3x - 28/ x + 7

(-7, 0) are the coordinates of the function.

Step-by-step explanation:

The given function is f(x) = (x²+3x-28)/(x+7).

We have to find the coordinates of hole of the given function.

To find the coordinates of the hole we will find the factors of the numerator first.

x² + 3x - 28 = x²+ 7x - 4x -28

= x(x + 7) - 4(x + 7)

= (x + 7)(x - 4)

Now we know that factor (x + 7) is common as denominator therefore these factors will get cancelled.

Therefore x + 7 = 0

Or x = -7

and for x = -7 the value of y = (x²+3x-28)/(x+7) = 0

Therefore the coordinates of the hole of the given function is (-7, 0).

answer: 19 is   2

step-by-step explanation: i just looked at your answer and wrote it down

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.