The length of a rectangle is 8 feet more than its width. if the width is increased by 4 feet and the length is decreased by 5 feet, the area will remain the same. find the dimensions of the original rectangle.

answer and ill give u brainliest

W = 12 L=20

Step-by-step explanation:

1.  Make all sides a function of width

2. since area is width times length, multiply to find area

So rectangle 1 area is W times L

=W x ( W + 8)

Rectangle 2 is (W+4) x (W+3),

The trick to this one is Since the original length = W+8 you decrease it by 5,  it becomes W+3

3. Set both rectangles as equal in the balanced equation and solve

So

W ( W +8) = (W+4)(W+3)

W^2 +8W = W^2 + 7W + 12

W=12

Insert into original equation... W=12 and L=(W+8) = 20

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐