Nthe recursive formula f(n) = f(n - 1) + 5, the value of the previous term is represented by

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Select the correct statement about the function represented by the table

If f(x) = 4 - xand g(x) = 6x, which expression is equivalent to (g-1)(3)? 6-3-(4 + 3)2 6-3-(4-32) 6(3) - 4+32 6(3)-4-32