Me with this trigonometry question:

The distance from A to B is 736.2 to the nearest tenth foot

Step-by-step explanation:

In ΔCAB

∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A

∴ m∠CAD = m∠ACB + m∠ABC

∵ m∠ABC = 20°

∴ m∠ACB = 30° - 20° = 10°

We will use the sin rule to find the distance AB

∵

∴ ≅ 736.2 to the nearest tenth foot

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get

they used 313 gallons of paint