Find the first four terms of the sequence an = 4n-6

The first four terms of the sequence are-6, -2, 2 and 6

Step-by-step explanation:

The given sequence is

In order to find the first four term of the sequence we put n =0, 1, 2 and 3.

For n =0

For n =1

For n =2

For n =3

Therefore, the first four terms of the sequence are

-6, -2, 2 and 6

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: