Firstly, Â factor the left side of your equation 
Set each of your terms to the number of 
 
 
![\boxed{\boxed{\bold{D.)x=\frac{-7}{4} [or]x=-4}}}](/tpl/images/0338/6672/1ad22.png)
Solve for x
4x^2+23x+28=0
a.) x=-4; 7/4
b.) x=4; -7/4
c.) x=4;...
Mathematics, 21.10.2019 17:40 bearbri4520
Solve for x
4x^2+23x+28=0
a.) x=-4; 7/4
b.) x=4; -7/4
c.) x=4; 7/4
d.) x=-4; -7/4
Answers: 1
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